The probability of success of three students X, Y and Z in the one examination are \( \frac{1}{5}, \frac{1}{4} \) and \( \frac{1}{3} \) respectively. Find the probability of success of at least two.

A \( \frac{1}{6} \)

B \( \frac{1}{4} \)

C \( \frac{1}{3} \)

D \( \frac{1}{2} \)

Solution

Correct Answer: Option A

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