Doubling the diameter of an orthodontic wire increases the force exerted by:

A 2 times

B 4 times

C 8 times

D 16 times

Solution

Correct Answer: Option D

The force exerted by an orthodontic wire is directly proportional to its cross-sectional area, which depends on the square of the diameter (A = πd²/4). Doubling the diameter increases the area by 4 times. Additionally, the moment of inertia, which influences wire stiffness, is proportional to the diameter raised to the fourth power (I ∝ d⁴). Therefore, doubling the diameter increases stiffness — and thus force exerted — by 2⁴ = 16 times. This explains why doubling the diameter results in a 16-fold increase in force exerted by the wire.

Reference: Graber's Orthodontics, 7th Edition.

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