A [r(cos θ + i sin θ)]^n = r^n[cos(nθ) − i sin(nθ)]
B [r(cos θ + i sin θ)]^n = r^n[cos(nθ) + i sin(nθ)]
C [r(cos θ + i sin θ)]^n = r[cos(θ/n) + i sin(θ/n)]
D r^n(cos θ + i sin θ) = cos(nθ) + i sin(nθ)
Correct Answer: Option B
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