অজৈব লবণ বিশ্লেষণ গ্রুপ-IIIA এর গ্রুপ বিকারক হচ্ছে-

A HCl+H2S

B NH4Cl+NH4OH

C NH4Cl+NH4OH+H2S

D NH4Cl+NH4OH+(NH4)2CO3

Solution

Correct Answer: Option B

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