In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A 1/3

B 3/4

C 7/19

D 8/21

Correct Answer: Option A

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue.

n(E) = 7

P(E)= 7 / 21

= 1 / 3