{(18)4 x (9)-4}/42 = ?
Solution
Correct Answer: Option B
$\frac{18^4 \times 9^{-4}}{4^2}$ $= \frac{(9 \times 2)^4 \times 9^{-4}}{(2^2)^2}$ $= \frac{9^4 \times 2^4 \times 9^{-4}}{2^4}$ $= 9^{4-4} \times 2^{4-4}$ $= 9^0 \times 2^0$ $= 1 \times 1$ $= 1$
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