if \( f(x) = e^x, g(x) = sin^{-1}x, h(x) = f(g(x)), then \frac{h^{\prime}}{h(x)} = ? \)

A \( e^{\sin^{- 1}{x}} \)

B \( \frac{1}{\sqrt{1 - x^{2}}} \)

C sin^-1x