Alpha particles (m = \( 6.68 × 10^{- 27} \) kg and q = +2e) accelerate to 2 keV through a potential difference V. They enter a magnetic field B = 0.2T perpendicular to their direction of motion. What is radius of their path?

A 35 mm

B 46 mm

C 32mm

D 41mm

Solution

Correct Answer: Option C

Practice More Questions on Our App!

Download our app for free and access thousands of MCQ questions with detailed solutions