Alpha particles (m = \( 6.68 × 10^{- 27} \) kg and q = +2e) accelerate to 2 keV through a potential difference V. They enter a magnetic field B = 0.2T perpendicular to their direction of motion. What is radius of their path?
A 35 mm
B 46 mm
C 32mm
D 41mm
Solution
Correct Answer: Option C