Solubility product of Al(OH)3 is \( 3.7 × 10^{- 15} \) .What will be the solubility of Al(OH)3 in mol/L unit?

A \( 1.081 × 10^{- 4} \)

B \( 1.424 × 10^{- 2} \)

C \( 7.242 × 10^{- 3} \)

D \( 7.242 × 10^{- 2} \)

Solution

Correct Answer: Option A

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