Bangladesh uses \( 1.2 \times 10^{17} \mathrm{~J} \) of electrical energy per year.If all this energy came from the fission of \( { }^{235} \mathrm{U} \) at Ruppur nuclear power plant which releases \( 200 \mathrm{MeV} \) per fission event .How many killogramof \( { }^{235} \mathrm{U} \) would be used per year? \( \left(1 \mathrm{amu}=1.6605 * 10^{-27} \mathrm{~kg}\right) \)

A 1463.87kg

B 1250.65kg

C 1360.56 kg

D 1420.55kg

Solution

Correct Answer: Option A

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