If tanx =ntany, n e R⁺, then the maximum value of sec²(x-y) is equal to-

A \( \frac{\left ( n + 1 \right )^{2}}{\left ( 2 n \right.} \)

B \( \frac{\left ( n + 1 \right )^{2}}{n} \)

C \( \frac{\left ( n + 1 \right )^{2}}{2} \)