Sum of three consecutive multiples of 3 is 396. Find the largest number.
Solution
Correct Answer: Option B
মনেকরি, 3 এর তিনটি ধারাবাহিক গুণনীয়ক = x, x + 3, x + 6
প্রশ্নমতে, x + x + 3 + x + 6 = 396
=> 3x + 9 = 396
=> 3x = 387
=> x = 129
∴ বড় সংখ্যাটি = 129 + 6 = 135
প্রশ্নমতে, x + x + 3 + x + 6 = 396
=> 3x + 9 = 396
=> 3x = 387
=> x = 129
∴ বড় সংখ্যাটি = 129 + 6 = 135
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