12 +22 +33 +. . . . . .+(40)2 = কত ?
Solution
Correct Answer: Option B
12 +22 +33 +. . . . . .+(40)2
\(\frac{{40(40 + 1)(2.40 + 1)}}{6} = \frac{{40 \times 41 \times 81}}{6} = 22140\)
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