If x is the average (arithmetic mean) of m and 9 ,y is the average of 2m and 15 ,and z is the average of 3m and 18 ,what is the average of x,y, and z in terms of m ?
Solution
Correct Answer: Option B
এখানে ,
x=(m+9)/2
বা,2x=m+9.......(i)
y=(2m+15)/2
বা,2y=2m+15........(ii)
এবং z=(3m+18)/2
বা,2z=3m+18.........(iii)
(i)+(ii)+(iii)
2x+2y+2z=m+9+2m+15+3m+18
বা,2(x+y+z)=6m+42
বা,x+y+z=3m+21
বা,(x+y+z)/3=m+7
x=(m+9)/2
বা,2x=m+9.......(i)
y=(2m+15)/2
বা,2y=2m+15........(ii)
এবং z=(3m+18)/2
বা,2z=3m+18.........(iii)
(i)+(ii)+(iii)
2x+2y+2z=m+9+2m+15+3m+18
বা,2(x+y+z)=6m+42
বা,x+y+z=3m+21
বা,(x+y+z)/3=m+7
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