3+1=4;

4+2=6;

6+3=9;

9+4=13;

13+5=18

Organization of the Petroleum Exporting Countries (OPEC) is an intergovernmental organization of 13 petroleum-exporting nations, founded in 1960 by the first five members, and headquartered since 1965 in Vienna, Austria. The 13 countries account for 40 percent of global oil production and 73 percent of the world's "proven" oil reserves, making OPEC a major influence on global oil prices.

২০১৪ সালে ব্রাজিলে হয়েছে। ২০১৮ সালে হবে রাশিয়াতে এবং ২০২২ সালে হবে কাতারে।

1. Chittagong Stock Exchange (CSE) & 2. Dhaka Stock Exchange (DSE)

(a-b)/3.5=4/7 =>(a-b)=4/7(3.5) =>(a-b)=14/7 =>(a-b)=2 Then a is greater than b since we got a-b=2

We continuously use cube, sphere and circle and their equations in mathematics. But their is no equation for pyramid nor that we use pyramid in mathematics.

A tricky question. One might ignore minor details in a question while giving the exam for a long time. It is mandatory to read the question very carefully and not to miss any word from the question.

In one minute, Susan, does one page:

(5/10)=1/2

Mary, does one page:

(10/5)=2

So, both do :

Net-work: (2+1/2)=5/2

Thus ,

1 minute work done: 5/2

So, In 30-minutes :  30 * (5/2) = 75 pages

Time = Distance / Speed

Time to travel 95 miles at 50 miles per hour = 95/50 < 2 hours.

Time to travel 125 miles at 60 miles per hour = 125/60 > 2 hours.

Note that you save time by not calculating the exact values of Quantity A and Quantity B.

y = -2

এই মান প্রথম সমীকরণে বসিয়ে পাই,

x = 2 * (-2) + 3

x = -4 + 3

x = -1

Thus,

Quantity A = x = -1

Quantity B = -1

13=13w/(1-w)

hence 13-13w=13w(on cross- multiplication)

w=1/2

So,

2*(1/2)*2 = 2

2 ^ a = 2(2) + a by definition of ^

a ^ 3 = 2(a) + 3 by definition of ^

Equate these two expressions:

2(2) + a = 2(a) + 3

Solve for a:

4 + a = 2a + 3

a = 1

At First,

M men contributed to Tk. D

1 man contributed to Tk. D / M

After 3 men leaving,

(M - 3) contributed to Tk. D

so, 1 man contributed to Tk. D / (M - 3)

After 3 men leaving, the individual amount for each men increased. So, D / (M - 3) > D/M

Now,

Diference = {D / (M-3)} - (D/M)

= (DM - DM + 3D) / M * (M - 3)

= 3D / (M2 - 3M)

2/(a-b) – 5/(b-a)

= {2/ (-1)(b-a)} - 5/(b-a)

=  -2/(a-b) – 5/(b-a)

= -7/(b-a) Alternatively,

the answer could have been, "7/(a-b)", but there were no option "7/(a-b)"

1/2 × 3/4 × 8/4 × 8/2 × ½

= (1 * 3 * 8 * 8 * 1) / (2 * 4 * 4 * 2 * 2)

= 192 / 128

= 3 / 2

Tom:Dick:Harry => 100:60:40 => 5:3:2 The total bill was for 104+16 = $120

We can write this as: 5x + 3x + 2x = 120 => 10x = 120 => x = 12 So we can now find out how much each person contributed towards the final total bill. So Tom paid: 5 * 12 = 60 Dick paid 3 & 12 = 36 Harry paid 2 * 12 = 24

Therefore Tom paid $(60 - 24) = $36 more than Harry.

To solve an averages problem, you should multiply for the products of the average.

In this case, a 3.0 GPA after 3 semesters gives us 9. (3 times 3.)

We also know that after the fourth semester, the cumulative GPA is supposed to be a 3.1.

Hence, this multiplier’s product is 12.4. (3.1 times 4.)

Subtracting 9 from 12.4 gives you GPA  3.4.

b=2x/3 therefore, 2x/3 < 2 or x <3

6p=3 p=3/6 p=1/2  

Similarly, 3/q=15 15q=3 q=3/15 q=1/5  

Then, p-q=1/2-1/5 =(5-2)/10 =3/10

The average of 5 quantities is 6. Therefore, the sum of the 5 quantities is 5 * 6 = 30.

The average of three of these 5 quantities is 8. Therefore, the sum of these three quantities = 3 * 8 = 24

The sum of the remaining two quantities = 30 - 24 = 6. Average of these two quantities = 6 / 2 = 3

Let son's age = x father's age =3x .. After 15 years son's age = x+15 father's age = 3x+15 .. 3x+15=2(x+15) 3x+15=2x+30 x=15 Father's present age = 3x = 45

x = -1

so,

[(-1)4 + (-1)3 + (-1)2 + (-1)]

= [1 - 1 + 1 - 1]

{Even number of power changes the Plus/Minus sign, but in Odd number of power the sign remains unchanged}

= 0

New length is 14-x and new width is 10+x. Since the new figure is a square we have that 14-x = 10+x. So 2x = 4 x = 2. So new length and new width are 12 each and new area is 12^2 = 144. initial area is 14*10 = 140. So area is changing by 144-140 = 4.

Let the average weight of the 59 students be A. So the total weight of the 59 of them will be 59 * A.

The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45 When this student is also included, the average weight decreases by 0.2 kgs.

Thus,

(59A + 45) / 60 = A - 0.2

=> 59A + 45 = 60A - 12 => 45 + 12 = 60A - 59A => A = 57

Thurs + Fri + Sat = 24 * 3 = 72

Sat = 27

So, Thurs + Fri = 72 - 27 = 45

Again,

Wed + Thurs + Fri = 25 * 3 = 75

or, Wed = 75 - (Thurs + Fri)

or Wed = 75 - 45

          = 30