A worker was hired for 7 days. Each day, he was paid Tk. 10 more than what he was paid for the previous day of work. The total amount he was paid in the first 4 days of work equaled the total amount he was paid in the last 3 days. What was his starting pay?

A Tk. 90

B Tk. 138

C Tk. 150

D Tk. 160

Solution

Correct Answer: Option A

 মনেকরি,starting payment = x টাকা

∴ ২য় দিনে (x + 10) টাকা
৩য় দিনে (x + 20) টাকা
৪র্থ দিনে (x + 30) টাকা
৫ম দিনে (x + 40) টাকা
৬ষ্ঠ দিনে (x + 50) টাকা
৭ম দিনে (x + 60) টাকা

প্রশ্নমতে,

x + (x + 10) + (x+20) + (x + 30) = (x+40) + (x + 50) + (x + 60)

⇒ 4x + 60 = 3x + 150

⇒ 4x - 3x = 150-60

⇒ x = 90

∴ starting payment ছিল 90 টাকা

 

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