A train went 300 miles from City X to City Y at an average rate of 80 mph. At what speed did it travel on the way back if its average speed for the whole trip was 100 mph?
Solution
Correct Answer: Option C
total time = time of leg one plus time of leg two = 6 hours and time of leg one = 300 miles / 80mph = 3.75 hours, so:
6 = time of leg one + 3.75, therefore time of leg one = 2.25.
speed during leg two = distance of leg two divided by time = 300 miles / 2.25 = 133.3... mph
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