Three boys agree to divide a bag of marbles in the following manner. The first boy takes one more than half the marbles. The second takes a third of the number remaining. The third boy finds that he is left with twice as many marbles as the second boy. The original number of marbles is -

A 38

B 36

C 32

D Cannot be determined

Solution

Correct Answer: Option D

মনেকরি,
মার্বেলের সংখ্যা = x
১ম বালক নেয় = (x/2) + 1
অবশিষ্ট = x - {(x/2) + 1}
          = x - (x/2) - 1
          = (x/2) - 1
∴ ২য় বালক নেয় = 1/3{(x/2) - 1}
                    = (x/6)- (1/3)
অবশিষ্ট = {(x/2) - 1)- (x/6)- (1/3)}
          = {(x/2) - 1-(x/6) + (1/3)}
          = {(x/2) - (x/6)} - {1 - (1/3)}
          = {(3x - x)/6} - {(3 - 1)/3}
          = 2x/6 - 2/3
          = x/3 - 2/3

প্রশ্নমতে,
  x/3 - 2/3 = 2{(x/6)- (1/3)}
⇒ x/3 -  2/3 = x/3 - 2/3
⇒ x/3 -  x/3 = 2/3 - 2/3
⇒ 0 = 0
যা হতে স্পষ্ট যে, মার্বেলের সংখ্যা নির্ণয় করা সম্ভব নয়।

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