Three boys agree to divide a bag of marbles in the following manner. The first boy takes one more than half the marbles. The second takes a third of the number remaining. The third boy finds that he is left with twice as many marbles as the second boy. The original number of marbles is -
A 38
B 36
C 32
D Cannot be determined
Solution
Correct Answer: Option D
মনেকরি,
মার্বেলের সংখ্যা = x
১ম বালক নেয় = (x/2) + 1
অবশিষ্ট = x - {(x/2) + 1}
= x - (x/2) - 1
= (x/2) - 1
∴ ২য় বালক নেয় = 1/3{(x/2) - 1}
= (x/6)- (1/3)
অবশিষ্ট = {(x/2) - 1)- (x/6)- (1/3)}
= {(x/2) - 1-(x/6) + (1/3)}
= {(x/2) - (x/6)} - {1 - (1/3)}
= {(3x - x)/6} - {(3 - 1)/3}
= 2x/6 - 2/3
= x/3 - 2/3
প্রশ্নমতে,
x/3 - 2/3 = 2{(x/6)- (1/3)}
⇒ x/3 - 2/3 = x/3 - 2/3
⇒ x/3 - x/3 = 2/3 - 2/3
⇒ 0 = 0
যা হতে স্পষ্ট যে, মার্বেলের সংখ্যা নির্ণয় করা সম্ভব নয়।