If whole amount is x

Then C gets = x - 3x/10 - x/4

                    = (40x - 12x -10x)/40

                    = 18x/40

Now, A/Q,

18x/40 = 81 tk

18x = 81*40 = 3240

x = 3240/18 = 180

Now,

B gets = x/4 = 180/4 = 45 tk

32*32= 1024

No other option can be derived that way.

let the number be X

now,

1/3 * 1/4 * X = 15

or, 1/12*X = 15

or, X = 15*12 = 180

Thus,

(3/10) * X = (3/10) * 180 = 3 * 18 = 54

35% of a number is = 35*X/100

50% of the number is = 50*X/100

Now,

A.Q

50*X/100 - 35*X/100 = 12

or, (50*X - 35*X)/100 = 12

or, 15*X / 100 = 12

or, X = 12* 100/ 15

or, X = 80

profit = S.P -C.P S.P = 2Y C.P = X PROFIT = 3(Y-X)= (2Y-X) = 3Y-3X-2Y+X = 1Y-2X (i.e)Y=2X : Profit = (Y-X)(i.e) =(2x-x)=Rs.x Profit% = C.P/profitX100= X/X*100=100%

Let the numbers be 3x, 4x and 5x Then,

9x2 + 16x2 + 25x2 = 1250

<=> 50x2 = 1250

<=> x2 = 25

<=> x = 5.

Sum of numbers = (3x + 4x + 5x) = 12x = (12 * 5) = 60.

The ratio is = X:Y = 2:3

Thus,

2a/3a = 40,000/ Y

or, Y = 40,000*3a/2a = 40,000*3/2 = 60,000

5 men = 19 days 3 men = 5/3 X 19 = 31.67 days 9 women = 19 days 6 women = 9/6 X 19 = 28.5 days 3 men + 6 women in 1 day = 1/31.67 + 1/28.5 = = 0.0315756 + 0.0350877 = 0.0666633 = 667 / 10,000 So they will complete the work in 10,000/667 = 14.99 days

If A can do a piece of work in n days, then A's 1 day's work = 1/n

(A + B + C)'s 1 day's work = (1/24 + 1/6 + 1/12) = 7/24

So, all the three together will complete the job in 24/7 days

or, 33/7

Work done by the leak in 1 hour = (1/2 - 3/7) = 1/14

Leak will empty the tank in 14 hrs.

Speed while going = 40 km/hr Speed while returning = 150% of 40 = 60 km/hr

Average speed = 2xy/(x+y)

                        = 2*40*60/(40+60)

                        = 4800/100 = 48 kmph

Convert 45km to m i.e. 45000m & 1hr=3600sec.

Then, 45000/3600sec. therefore 12.5m/sec. Total distance to be covered is 360m + 140m = 500m

Then, time required to pass the bridge is 500m/12.5m/s = 40sec.

Let breadth =x metres. Then length =(115x/100)metres.  

x∗115x/100=460

x2=(460*100/115)

x2=400

x=20

To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.

While A covers 3 m, B covers 4 m.

While A covers 360 m, B covers = (4*360/3) m = 480m

Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.

The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.

Required number of ways= 6!/ (1!)(2!)(1!)(1!)(1!)

                                      = 360

Error %= error / true value

but, here.. error= true value-false value

ie., error=(5/3)-(3/5)=16/5

so the error % will be equal to (16/5)/(5/3)=64%

(since, true value is 5/3)

(x+4)/y = x/y+2/3

Or, x/y + 4/y =  x/y + 2/3

Thus,

4/y = 2/3

Or, 2y = 12

Or, y = 12/2 = 6

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

 (2x + 2) + 2 

The Government  has so far established three Juvenile Development Centres under the provision of the Children Act, 1974, each of which consists of one Juvenile Court, one Remand Home and one Training Institute. These Centres are :

(i)       National Juvenile Development Centre, Tongi, Gazipur (for 200 boys) (ii)      National Juvenile Development Centre, Konabari, Gazipur (for 150 girls) (iii)     Juvenile Development Centre, Jessore (for 150 boys )

হয়, বাজী > ঘোড়া, অশ্ব, ঘোটক, তুরগ, তুরঙ্গ, তুরঙ্গম

If numbers are 12 & 5

.:. (12+5) X 12 = 204

(12-5) X 5 = 35

Ans. 12, 5

Let, the numbers be x, x+1, x+2, x+3, x+4, x+5, x+6

Sum of 7 consecutive number be= 20X7= 140

A.T.Q. 

x, x+1, x+2, x+3, x+4, x+5, x+6= 140

7x+21 = 140

7x = 119

.:. x= 17   .:. The largest number= x+6= 17+6 = 23 (Ans.)  

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