(2x-1 )2 \( \div \) x-5 is equal to

(2x^-1 )² \( \div \) x^-5 is equal to

A 2x²

B 4x

C 4x²

D 4x³

Correct Answer: Option D

Solution:

দেওয়াআছে, (2x^-1 )² \( \div \) x^-5 = 2² \( \times \) x^-2 \( \div \) x^-5 = \(\frac{{4{x^{ - 2\;}}}}{{\;{x^{ - 5}}}}\) = 4x^-2+5 = 4x³