\(\frac{1}{3} + \frac{2}{3} + \frac{3}{y} = \frac{{23}}{{12}}\), then y = ?

A 2

B 3

C 4

D None

Correct Answer: Option D

Solution:

\(\frac{1}{3} + \frac{2}{3} + \frac{3}{y} = \frac{{23}}{{12}}\)

=> \(\frac{3}{y} = \frac{{23}}{{12}} - (\frac{1}{3} + \frac{2}{3})\) => \(\frac{3}{y} = \frac{{23}}{{12}} - \frac{3}{3}\)

=> \(\frac{3}{y} = \frac{{23}}{{12}} - 1\) => \(\frac{3}{y} = \frac{{23 - 12}}{{12}}\)

=> \(\frac{3}{y} = \frac{{11}}{{12}}\) => 11y = 36 y = \(\frac{{36}}{{11}}\)