City B is 8 miles east of City A. City C is 6 miles north of city B. City D is 16 miles east of City C and City E is 12 miles North of City D. What is the distance from City A to City E?

A 10 miles

B 20 miles

C 24 miles

D 30 miles

Correct Answer: Option D

By law of Right angle triangle,

we can find oiut the distance of AC and CE. Thus, the entire distance from A to E.

Now,

AC = √(AB2 + CB2) = √(82 + 62) = √(64 + 36) = √(100) = 10

Again, CE = √(CD2 + DE2) = √(162 + 122) = √( 256+ 144) = √(400) = 20

Thus,

AE = AC+ CE = 10 + 20 = 30 miles