At 3 A.M. the temperature was 13° below zero. By noon, it had risen to 32°. What was the average hourly increase in temperature?

A    (19/9)°

B    (19/6)°

C    5°

D    7.5°  

Solution

Correct Answer: Option C

 

Total Difference = 32 - (-13) = 45

Average hourly increase = 45/9=5

 

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