A worker was hired for 7 days. Each day, he was paid Tk. 10 more than what he was paid for the previous day of work. The total amount he was paid in the first 4 days of work equaled the total amount he was paid in the last 3 days. What was his starting pay?
Solution
Correct Answer: Option A
payment for day 1 = x
payment for first 4 days = x + x +10+x+20+x+30 = 4x +60
payment for last 3 days = x+40+x+50+x+60 = 3x + 150
now, A/Q,
4x + 60 = 3x + 150
x = 90
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