male engineering student = 25*120/100 = 30

female engineering student = 20*100/100 = 20

total engineering student = 30 + 20 = 50

now,

male engineering students that passed = 20*30/100 = 6

female engineering students that passed = 25*20/100 = 5

total students that passed = 6 + 5 = 11

now,

percentage of engineering students that passed the exam = 11*100/50 = 22%

let, portion with 5% interest be x

then,

5x/100 + 7*(1200 - x)/100 = 72

5x + 7*(1200 - x) = 7200

5x + 8400 - 7x = 7200

- 2x = 7200 - 8400

- 2x = - 1200

x = 600

As you go through the Options: Option (B) will satisfy the conditions.

X:Y:Z = 2:3/2:1 = 4:3:2

now, lowest salary is earned by Z, as we can see from the ratio.

Z's salary = 2*90000/9 = 20000 tk

payment for day 1 = x

payment for first 4 days = x + x +10+x+20+x+30 = 4x +60

payment for last 3 days = x+40+x+50+x+60 = 3x + 150

now, A/Q,

4x + 60 = 3x + 150

x = 90

Let the number of male kids be x.

For M,

number of brothers = x

number of sisters = x

number of girl kid = x+1

For N,

number of male kid = x

number of brothers = x-1

number of sisters = 2(x-1)

now, A/Q,

x+1 + x = x + 2(x-1)

2x + 1 = x  + 2x – 2

2x +x -2x =1+2

x = 3 number of male kid = 3

number of girl kid = 3 + 1 = 4

Total kids = 3 + 4 = 7

smaller tiles = 2*1 = 2 sq ft

40 smaller tiles cover = 40*2 = 80 sq ft area

now,

area of bigger tiles = 2*4 = 8 sq ft

tiles required to cover the same floor = 80/8 = 10 tiles

Sol: 50% (n) + 60% (100 ) = 55% (n + 100) Solving we get n = 100

n + 100 = 100 + 100 = 200

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