The present ages of three persons are in the ratio of 4:7: Eight years ago, the sum of their ages was What are their present ages in years?

A    8,20,28

B    16,28,36

C    20,35,45

D    12,21,27

Solution

Correct Answer: Option B

 

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

 

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