Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Rohit’s age?

A 2 times

B 2.5 times

C 3.5 times

D 3 times

Correct Answer: Option A

Father's age = 4 X Son's age

Father's age + 8 years = 2.5 (Son's age + 8 years)

If we subtract,

- 8 years = 1.5 Son's age -20 years

Son's age = 8 years

Father's age = 32 years

After further 8 years (total 16 years),

Father's age = 48

Son's age = 24