Three coins are tossed. Find the probability of exactly 2 heads -

A (3/8)

B (1/2)

C (1/8)

D None

Solution

Correct Answer: Option A

n(S) = 23 = 8 
Let E = Event of getting exactly two heads,
= {(H, H, T), (H, T, H), (T, H, H)}
= n(E)
= 3

Required probability = 3/8

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