If a + b + c = 0, the value of (a2/bc) + (b2/ca) + (c2/ab) is -
Solution
Correct Answer: Option D
a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - ab - bc - ca)
a + b + c = 0, then a3 + b3 + c3 - 3abc = 0
∴ a3 + b3 + c3 = 3abc
(a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc
= 3
a + b + c = 0, then a3 + b3 + c3 - 3abc = 0
∴ a3 + b3 + c3 = 3abc
(a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc
= 3
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