Ten years ago, A was half of B in age. If the ratio of their present age is 3:4, what will be the total of their present ages?
Solution
Correct Answer: Option D
Let A's age 10 years ago = x years. Then, B's age 10 years ago = 2x years. (x + 10) / (2x+ lO) = 3/4 => x = 5. So, the total of their present ages =(x + 10 + 2x + 10) = (3x + 20) = 35 years.
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