In a sugar-water solution, the ratio of water to sugar is 8: If you add 2 kgs of sugar, the ratio becomes 2: What was the amount of sugar in the original solution? 

A    4.5

B    5

C    8

D    6

Solution

Correct Answer: Option D

 

Let sugar be x and water be y,

Then,

y:x = 8:3

or, y/x = 8/3

or, 3y = 8x

or, y = 8x/3 ............................. (1)

Again,

y:(x+2) = 2:1

or, y/(x+2) = 2/1

or, y = 2x + 4

Now,

8x/3 = 2x + 4

or, 8x = 6x + 12

or, 8x - 6x = 12

or, 2x = 12

or, x = 6

Thus, originaly, there were 6 kg of sugar.

 

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