125 gallons of a mixture contains 20% water. What amount of additional water should be added such that the water content is raised to 25%?
সমাধান
সঠিক উত্তর: Option D
Let, x gallons water should be added.
Here, 125 gallons of a mixture contains 20% water is (125× 20/100)= 25 gallons
According to the question,
25+x = (125+x)×25/100
=> 25+x = (125+x)×1/4
=> 4(25+x) = 125+x
=> 100+4x = 125+x
=> 4x-x=125-100
=> 3x=24
=> x=24/3
So, x=81/3
So, 81/3 gallons water should be added. (Ans.)
