Correct Answer: Option C
Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB. We may consider the two cases as under :
3 8 5 21 Case I : ← C ↔ B ↔&n
Number of persons between A and C = (8 - 6) = 2. Clearly, number of persons in the queue = (3 + 1 + 2 + 1 + 21) = 28. Now, 28 < 40. S
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