A student first reduced a number by 20% and then increased it again by 20%. If the difference between the last number and the original number is 8, then the original number was?
Solution
Correct Answer: Option A
Suppose, Total marks= 100
20% reduced= 80
Then, 20% increased=80+80 of 20%=96
Difference=100-96=4
4 difference then orginal number =100
8 difference then orginal number=(100×8)/4
=200
20% increased= 96%
Difference = 100-96 = 4
Difference is 4 when the original number is 100
,, ,, 8 ,, ,, = 200
Practice More Questions on Our App!
Download our app for free and access thousands of MCQ questions with detailed solutions