The number of chocolates with Rani when multiplied by 12, gives the number of chocolates with Kajol, which are as much above 130 as the number of chocolates with Rani are below 130. The average of the number of chocolates with Rani and Kajol is:
Solution
Correct Answer: Option B
Let number of chocolates with Rani = x, then according to the question,
Number of chocolates with Kajol = 12x,
We are given that,
12x – 130 = 130 – x
⇒ 13x = 260,
⇒ x = 20,
∴ Number of chocolates with Kajol = 12 × 20 = 240
∴ Total number of chocolates with Rani and Kajol together = 240 + 20 = 260
We know that, formula for average-
\(\Rightarrow \left\{ {{A_E} = \frac{{{S_E}}}{{{n_E}}}\;or\;{S_E} = {A_E} \times {n_E}} \right\}\)
Where,
SE = sum of entities,
nE = number of entities,
AE = Average of entities.
Hence, average number of chocolates with Rani and Kajol together = (20+240)/2=130
Alternatively-
[Simply we are given that no. of chocolates with Rani and Kajol are equidistant from 130, one is less and other is more by the same no, hence average would be 130 itself.]
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