In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘a’ and ‘b’ and mark correct answer. I. a√25 + 2b = √961 II. 3a + (2401)1/4b = 36

In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘a’ and ‘b’ and mark correct answer.

I. a√25 + 2b = √961

II. 3a + (2401)^1/4b = 36

A a > b

B a ≥ b

C a < b

D a ≤ b

E a = b or the relation cannot be determined

Solution

Correct Answer: Option A

We will solve both the equations separately.

Equation I:

a√25 + 2b = √961

Here √25 can only be evaluated as 5

⇒ 5a + 2b = 31

Equation II:

3a + (2401)^1/4b = 36

⇒ 3a + 7b = 36

Multiplying the simplified values of equation (I) by 3 and that of (II) by 5, we get,

b = 3

Putting this value of y in the simplified value of equation (I), we get

a = 5

∴ a > b

Solution

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