sinθ = 3/5, 0 < θ < (π/2) হলে tanθ = ?
সমাধান
সঠিক উত্তর: Option A
sinθ = 3/5
∴cosθ = √(1 - sin2θ)
= √( 1 - 9/25)
= √(16/25)
= 4/5
∴ tanθ = sinθ/cosθ
= (3/5)/(4/5)
= (3/5) × (5/4)
= 3/4
∴cosθ = √(1 - sin2θ)
= √( 1 - 9/25)
= √(16/25)
= 4/5
∴ tanθ = sinθ/cosθ
= (3/5)/(4/5)
= (3/5) × (5/4)
= 3/4
