If 4y – 3x = 5, what is the smallest integer value of x for which y>100?

Since 4y - 3x = 5

=>4y = 5 + 3x

=>4y - 5 = 3x

=>3x = 4y - 5

if you look at the equation you will notice that x is directly proportional to  y

therefore if we increase the value of y, x is also increases.

If the value of y is smallest then the x is also smallest.

Since y>100

therefore the smallest value of y = 101

therefore the equation is  3x = 4 X 101 - 5

=> 3x = 404 -5

=> x = 399/3

=> x = 133