In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
সমাধান
সঠিক উত্তর: Option A
Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue.
n(E) = 7
P(E)= 7 / 21
= 1 / 3
