In how many ways can 5 boys and 7 girls be arranged in a row so that no two boys are together?

A 5! × 7!

B ⁷p₂ × 5!

C 7! × 8p₅

D 7p₅× 7!

E None of these

Correct Answer: Option C

As no two boys are to be together, we need the presence of a girl between every two boys.

The seven girls can be arranged in 7! Ways.

_G_G_G_G_G_G_G_

The five boys can be arranged in 8 available gaps in ⁸P₅ ways.

∴ the total number of arrangements = 7! × ⁸p₅