In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I. x2 + 3x + 2 = 0 II. 2y2 = 5y

In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer

I. x² + 3x + 2 = 0

II. 2y² = 5y

A x < y

B x > y

C x ≤ y

D x ≥ y

E x = y

Solution

Correct Answer: Option A

We will separately solve both equations.

Equation 1:

x² + 3x + 2 = 0

⇒ x² + 2x + x + 2 = 0

⇒ x (x + 2) + 1 (x + 2) = 0

⇒ (x + 2) × (x + 1) = 0

⇒ x = -2 or, x = -1

Equation 2:

2y² = 5y

⇒ 2y² – 5y = 0

\(\Rightarrow 2y \times \left( {y - \frac{5}{2}} \right) = 0\)

⇒ y = 0 or, y = \(\frac{5}{2}\)

Both values of y are positive while both values of x are negative.

∴ y > x

Solution

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