In the following question, there are two equations. Solve them and give answer
I. 20P2 – 17P + 3 = 0
II. 20Q2 – 9Q + 1 = 0
Solution
Correct Answer: Option D
I. 20P2 – 17P + 3 = 0
On doing factorization
⇒ 20P2 – 5P – 12P + 3 = 0
⇒ 5P (4P – 1) – 3 (4P – 1) = 0
⇒ (4P – 1) (5P – 3) = 0
⇒ P = 1/4, 3/5
⇒ P = 0.25, 0.60
II. 20Q2 – 9Q + 1 = 0
On doing factorization
⇒ 20Q2 – 5Q – 4Q + 1 = 0
⇒ 5Q (4Q – 1) – 1 (4Q – 1) = 0
⇒ (4Q – 1) (5Q – 1) = 0
⇒ Q = 1/4, 1/5
⇒ Q = 0.25, 0.20
On taking Q = 0.25
⇒ P ≥ Q (for both the values of P) . . . . equation 1
On taking Q = 0.20
⇒ P > Q (for both the values of P) . . . . equation 2
From equation 1 and 2
P ≥ Q
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