A boy was asked to find 8/9th of a fraction. He made a mistake of dividing the fraction by 8/9 and so got an answer which exceeds the correct answer by 17/54. Find the original fraction?

A 2/3

B 3/4

C 4/3

D 3/5

E None of these

Solution

Correct Answer: Option C

Let the fraction be a/b

We consider fraction a/b = x

A boy was asked to find 8/9 th of a fraction. He made a mistake of dividing the fraction by 8/9 and so got an answer which exceeds the correct answer by 17/54

\(\Rightarrow \frac{x}{{\frac{8}{9}}}\;-\frac{8}{9} \times x\; = \frac{{17}}{{54}}\)

⇒ 9x/8 – 8x/9 = 17/54

\(\begin{array}{l} \Rightarrow \;\frac{{9x \times 9 - 8x \times 8}}{{72}} = \;\frac{{17}}{{54}}\\ \Rightarrow {\rm{\;}}\frac{{81x - 64x}}{{72}} = \frac{{17}}{{54}} \end{array}\)

⇒ 17x/72 = 17/54

\(\Rightarrow {\rm{\;x\;}} = \frac{{17}}{{54}}\; \times \frac{{72}}{{17}}\)

⇒ x = 4/3

So, our fraction a/b = x = 4/3

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