A polynomial f(x) = x4 – 11x3 + 31x2 – 46x + 20 is defined. When it is divided by x2 – 3x + n, the remainder left is q. Find the product of n and q.
Correct Answer: Option D
Let the quotient after division be x2 + ax + b.
⇒ (x2 – 3x + n)( x2 + ax + b) + q = x4 – 11x3 + 31x2 – 46x + 20
⇒ x4 + (a – 3)x3 + (n – 3a + b)x2 + (an – 3b)x + bn + q = x4 – 11x3 + 31x2 – 46x + 20
Comparing, we get a = -8, n – 3a + b = 31, an – 3b = -46, bn + q = 20.
Put value of a, we get n + b = 7, 8n + 3b = 46
Solving, we get n = 5, b = 2.
Now, bn + q = 20
⇒ q = 20 – 5× 2 = 10
∴ Product of n and q will be 50.
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