Rajan is travelling at a speed of 24 km/h reaches a particular place 10 minutes early but when he travels at a speed of 16 km/h he reaches the same place from the same point 10 minutes late. Find the distance.
Solution
Correct Answer: Option D
We know that formulae:
→ Speed = Distance/Time
→ When someone reaches destination ‘a’ hours before than usual time, walking with speed ‘u’ and he reaches destination ‘b’ hours later than usual time, walking with speed ‘v’, then –
Travelled distance = \(\frac{{u \times v}}{{u \sim v}} \times \left( {a + b} \right)\)
{Where ‘u’ and ‘v’ are faster and slower speeds in km/h respectively}
∴ Required distance \(= \frac{{24 \times 16}}{{24 - 16}} \times \left( {\frac{{10}}{{60}} + \frac{{10}}{{60}}} \right) = \frac{{48 \times 1}}{3} = 16\;km\)
Hence, the required distance is 16 km.
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