A bag contains 4 red balls, 6 White balls, 8 Green balls and 10 Black balls. If one ball is drawn at random, find the probability that it is Black.
Correct Answer: Option A
Let S be the sample space.
Then, total number of balls = (4 + 6 + 8 + 10) = 28 balls
Thus, n(S) = 28
Let E = event that the ball drawn is black
∵ There are 10 black balls in the bag
Thus, n(E) = 10
∴ Probability of occurrence of event;
P(E) = n(E)/n(S) = 10/28 = 5/14
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