Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4). The maximum value among the above three is

A a

B b

C c

D All equal

Correct Answer: Option C

a = (4 ÷ 3) ÷ 3 ÷ 4
= (4/3) x (1/3) x (1/4)
= (1/9)

b = 4 ÷ (3 ÷ 3) ÷ 4
= 4 ÷ 1 ÷ 4
= 4 x (1/1) x (1/4)
= 1

c = 4 ÷ 3 ÷ (3 ÷ 4)
= 4 ÷ 3 ÷ (3/4)
= (4/3) x (4/3)
= (16/9)

এখানে, (16/9)> 1 > (1/9) ; স্পষ্টত, বৃহত্তম সংখ্যা।