A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :
Correct Answer: Option A
Total money = Rs.[600*(25 \(\div\) 100)+1200 \(\times\) (50 \(\div\) 100)]= Rs. 750.
25 paise coins removed = Rs. (600 \(\times\) 12 \(\div\) 100) = 72.
50 paise coins removed = Rs. (1200 \(\times\) 24 \(\div\) 100)= 288.
Money removed =Rs.(72 \(\times\) 25 \(\div\) 100+288*50 \(\div\) 100) = Rs.162.
Required percentage = (162 \(\div\) 750 \(\times\) 100)% = 21.6 %.
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