A watch which gains uniformly ,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec.fast at 8 p.m on following sunday. when was it correct?
Solution
Correct Answer: Option B
This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast.
The watch gains \(5+5\frac{48}{60}\) min in a time of (7×24)+12 = 180 hours.
To show the correct time, it has to gain 5 min.
\(\frac{54}5min\rightarrow180hours\)
5min -> \(\left(\frac5{\displaystyle\frac{54}2}\times180\right)\)
\(83\frac13hrs=72hrs+11\frac13hrs=3days+11hrs+20min\)
So the correct time will be shown on wednesday at 7:20 PM
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